Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter Alcohols Phenols and Ethers. This page offers a step-by-step solution to the specific question from Exercise 1, Question 8: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.
Ortho and para nitrophenols are more acidic than phenol. Draw the resonance structures of the corresponding phenoxide ions.
Resonance structure of the phenoxide ion
Resonance structures of p-nitrophenoxide ion
Resonance structures of o-nitrophenoxide ion
It can be observed that the presence of nitro groups increases the stability of phenoxide ion.
The reaction between A and B is first order with respect to A and zero order with respect to B. Fill in the blanks in the following table:
| Experiment |
A/ mol L - 1 |
B/ mol L - 1 |
Initial rate/mol L - 1 min - 1 |
| I | 0.1 | 0.1 |
2.0 × 10 - 2 |
| II | -- | 0.2 |
4.0 × 10 - 2 |
| III | 0.4 | 0.4 | -- |
| IV | -- | 0.2 |
2.0 × 10 - 2 |
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Comments
why is it that in some books the resonance structures of o and p nitrophenol is given upto only the fifth resonating structure??
Para last structure is wrong correct it
In 5th resonating structure of p-isomer,double bonds should b b/w carbon no.2&3,4&5 but here double bonds are given b/w carbon no.1&2,4&5 which is not right.
How can oxygen have 3 lone pairs.
Yes you are right the last structure will not have a double bond with oxygen atom.only a single bond will be their in the last structure because the electron involved in making double bond between carbon and oxygen has been transferred to the oxygen atom
The structure of para is wrong as in the last step the topmost carbon is having 5 bonds which is not possible.