How many mL of 0.1 M HCl are required to | Class 12 Chemistry Chapter Solutions, Solutions NCERT Solutions

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter Solutions. This page offers a step-by-step solution to the specific question from Exercise 2, Question 6: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 6:

How many mL of 0.1 M HCl are required to react completely with 1 g mixture of Na2CO3 and NaHCO3 containing equimolar amounts of both?

Answer:

let the amount of Na2CO3 be x

& that of NaHCO3 be 1-x

Now moles of Na2CO3 = x / 106

& moles of NaHCO3 = 1-x / 84

Now according to question , number of moles of Na2Co3 = number of moles of NaHCO3

Therefore x / 106 = 1-x / 84

84x = 106-106x

84x +106x = 106

190x = 106

Or

x = 106 / 190 = 0.558

Therefore moles of Na2Co3 = 0.558 / 106 = 0.00526

&

moles of NaHCO3 = 1 - 0.558 / 84 = 0.0053

Now Hcl reacts with Na2Co3 & NaHCO3 as follows:

 

Na2Co3 + 2Hcl  2Nacl + H2o + CO2

NaHCO3 + Hcl  Nacl + H2o + CO2

 

From the above reactions, 1 mol of Na2Co3 will react with 2 mol of Hcl

Therefore 0.00526 mol of Na2Co3 will react with 2 x 0.00526 mol of Hcl & similarly 0.00526 mol of NaHCO3 will react with 0.00526 mol of Hcl

Total moles of Hcl required to react with mixture of of NaHCO3 & Na2Co3

= 2 X 0.00526 + 0.00526 =0.01578 mol

Also according to question 0.1 mol of 0.1 M Hcl is present in 1000 ml

Or

0.01578 mol of 0.1 M Hcl is present in (1000/0.1) x 0.01578 = 157.8 ml

Hence, 158 mL of 0.1 M of HCl is required to react completely with 1 g mixture of Na2CO3 and NaHCO3, containing equimolar amounts of both.


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Comments

  • Rishabh
  • Mar 19, 2020

Super duper smarttt


  • Ravi
  • Aug 05, 2019

Easy understanding method nice. Diaper for difficult questions..


  • Krysta
  • May 30, 2019

Perfect 👍


  • Kunalsharma
  • May 03, 2019

Good but it can be done in short also😍


  • Uttam
  • Apr 21, 2019

Thanks


  • Uttam
  • Apr 21, 2019

Thanks


  • Vikas
  • Apr 20, 2019

Thanks


  • Girjesh kumar
  • Apr 11, 2019

Very nice.


  • KRISHAN KUMAR
  • Apr 11, 2019

Hmm thank you. But still.........


  • Facebook
  • Mar 30, 2019

You are help me to solve this prnblem so thank you for it


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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 6: How many mL of 0.1 M HCl are required to react completely with 1 g mixture of Na2CO3 and NaHCO3 cont....