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Academic session 2026-27, Chapter 1 in the current curriculum.
Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter Solutions. This page offers a step-by-step solution to the specific question from Exercise 2, Question 6:
How many mL of 0.1 M HCl are required to react completely with 1 g mixture of Na2CO3 and NaHCO3 containing equimolar amounts of both?
. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.How many mL of 0.1 M HCl are required to react completely with 1 g mixture of Na2CO3 and NaHCO3 containing equimolar amounts of both?
let the amount of Na2CO3 be x
& that of NaHCO3 be 1-x
Now moles of Na2CO3 = x / 106
& moles of NaHCO3 = 1-x / 84
Now according to question , number of moles of Na2Co3 = number of moles of NaHCO3
Therefore x / 106 = 1-x / 84
84x = 106-106x
84x +106x = 106
190x = 106
Or
x = 106 / 190 = 0.558
Therefore moles of Na2Co3 = 0.558 / 106 = 0.00526
&
moles of NaHCO3 = 1 - 0.558 / 84 = 0.0053
Now Hcl reacts with Na2Co3 & NaHCO3 as follows:
Na2Co3 + 2Hcl 2Nacl + H2o + CO2
NaHCO3 + Hcl Nacl + H2o + CO2
From the above reactions, 1 mol of Na2Co3 will react with 2 mol of Hcl
Therefore 0.00526 mol of Na2Co3 will react with 2 x 0.00526 mol of Hcl & similarly 0.00526 mol of NaHCO3 will react with 0.00526 mol of Hcl
Total moles of Hcl required to react with mixture of of NaHCO3 & Na2Co3
= 2 X 0.00526 + 0.00526 =0.01578 mol
Also according to question 0.1 mol of 0.1 M Hcl is present in 1000 ml
Or
0.01578 mol of 0.1 M Hcl is present in (1000/0.1) x 0.01578 = 157.8 ml
Hence, 158 mL of 0.1 M of HCl is required to react completely with 1 g mixture of Na2CO3 and NaHCO3, containing equimolar amounts of both.
The reaction between A and B is first order with respect to A and zero order with respect to B. Fill in the blanks in the following table:
| Experiment |
A/ mol L - 1 |
B/ mol L - 1 |
Initial rate/mol L - 1 min - 1 |
| I | 0.1 | 0.1 |
2.0 × 10 - 2 |
| II | -- | 0.2 |
4.0 × 10 - 2 |
| III | 0.4 | 0.4 | -- |
| IV | -- | 0.2 |
2.0 × 10 - 2 |
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 6: How many mL of 0.1 M HCl are required to react completely with 1 g mixture of Na2CO3 and NaHCO3 cont....
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Comments
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