Calculate the mole fraction of benzene i | Class 12 Chemistry Chapter Solutions, Solutions NCERT Solutions

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter Solutions. This page offers a step-by-step solution to the specific question from Exercise 1, Question 2: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 2:

Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.

Answer:

Let the total mass of the solution be 100 g and the mass of benzene be 30 g.

∴ Mass of carbon tetrachloride = (100 - 30) g = 70 g

Molar mass of benzene (C6H6) = (6 × 12 + 6 × 1) g mol - 1

= 78 g mol - 1

∴ Number of moles of C6H6  =30/78 mol

= 0.3846 mol

Molar mass of carbon tetrachloride (CCl4) = 1 × 12 + 4 × 35.5

= 154 g mol - 1

∴ Number of moles of CCl4 = 70/154 mol

= 0.4545 mol

Thus, the mole fraction of C6H6 is given as:

= 0.3846 / (0.3846 + 0.4545)

= 0.458


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Comments

  • Aadil
  • Feb 27, 2021

Sir please tell me 0.385/(0.385+0.454


  • Andria
  • Sep 02, 2020

Thankyou sir


  • Swati
  • Mar 02, 2020

Very very helpful


  • Bhanu
  • Dec 28, 2019

Thanks


  • Sami sonare
  • Nov 16, 2019

Thank you sir


  • Mohammadi Shafiya
  • Oct 09, 2019

Thanks a lot😃!


  • Rishabh Singh Rajput
  • Sep 12, 2019

Thanks sir


  • Nidhi
  • Aug 19, 2019

Really helpful ✌️


  • Prince
  • Jul 18, 2019

MainBoling sir


  • Aaryan
  • Jul 18, 2019

Which is solute nd solvent


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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 2: Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.....