Given a G.P. with a = 729 and | Class 11 Mathematics Chapter Sequence and Series, Sequence and Series NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Mathematics - Chapter Sequence and Series. This page offers a step-by-step solution to the specific question from Exercise 3, Question 15: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 15:

Given a G.P. with a = 729 and 7th term 64, determine S7.

Answer:

a = 729

a7 = 64

Let r be the common ratio of the G.P.

It is known that, an = a rn–1

a7 = ar7–1 = (729)r6

⇒ 64 = 729 r6

rightwards double arrow r to the power of 6 space equals space 64 over 729
rightwards double arrow r to the power of 6 space space equals space open parentheses 2 over 3 close parentheses to the power of 6
rightwards double arrow r space equals space 2 over 3

Also, it is known that, 

S subscript n space equals space fraction numerator a space open parentheses 1 minus r to the power of n close parentheses over denominator 1 minus r end fraction

therefore space S subscript 7 space equals space fraction numerator 729 open square brackets 1 minus open parentheses begin display style 2 over 3 end style close parentheses to the power of 7 close square brackets over denominator 1 minus begin display style 2 over 3 end style end fraction
space space space space space space space space space space space space equals space 3 space cross times space 729 space open square brackets 1 minus open parentheses 2 over 3 close parentheses to the power of 7 close square brackets
space space space space space space space space space space space space equals open parentheses 3 close parentheses to the power of 7 space open square brackets fraction numerator open parentheses 3 close parentheses to the power of 7 space minus space open parentheses 2 close parentheses to the power of 7 over denominator open parentheses 3 close parentheses to the power of 7 end fraction close square brackets
space space space space space space space space space space space space equals space open parentheses 3 close parentheses to the power of 7 space minus open parentheses 2 close parentheses to the power of 7
space space space space space space space space space space space space space equals space 2187 space minus space 128
space space space space space space space space space space space space space equals space 2059


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Sequence and Series.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Comments

  • Mithun
  • Jul 16, 2018

It was helpful.thank you


  • Prashant
  • Jun 22, 2018

Too much helpful. ...


  • Chandradeep
  • Sep 16, 2017

Thanks a lot to Saral study who help us better pratice in math


  • Dhruv
  • Nov 11, 2016

Thanks for solution. ...


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Welcome to the NCERT Solutions for Class 11 Mathematics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 3 , Question 15: Given a G.P. with a = 729 and 7th term 64, determine S7.....