Find the 12th term of a G.P. whose | Class 11 Mathematics Chapter Sequence and Series, Sequence and Series NCERT Solutions

Current NCERT chapter

Academic session 2026-27, Chapter 8 in the current curriculum.

Welcome to the NCERT Solutions for Class 11 Mathematics - Chapter Sequence and Series. This page offers a step-by-step solution to the specific question from Exercise 3, Question 2:

Find the 12th term of a G.P. whose 8th term is 192 and the common ratio is 2.

. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 2:

Find the 12th term of a G.P. whose 8th term is 192 and the common ratio is 2.

Answer:

Common ratio, r = 2

Let a be the first term of the G.P.

∴ a8 = ar 8–1 = ar7

⇒ ar7 = 192

a(2)7 = 192

a(2)7 = (2)6 (3)

rightwards double arrow a equals fraction numerator open parentheses 2 close parentheses to the power of 6 cross times 3 space over denominator open parentheses 2 close parentheses to the power of 7 end fraction equals 3 over 2
s o
a subscript 12 space equals a r to the power of 12 minus 1 end exponent space equals space open parentheses 3 over 2 close parentheses open parentheses 2 close parentheses to the power of 11 equals open parentheses 3 close parentheses open parentheses 2 close parentheses to the power of 10 equals 3072

 


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Sequence and Series.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Comments

  • RUPAM BANERJEE
  • Mar 11, 2017

S.I. for 1 year = Rs. (2124-2016) = Rs. 108. S.I. for 2 years = Rs.(108 x 2) = Rs. 216. We know that, A = P + S.I. So, A = 2016 S.I. = 216 Principal, P = Rs. (2016-216) = Rs. 1800.


  • Kavya Gowda
  • Feb 23, 2017

A sum of money becomes ` 2016 in 2 years and ` 2124 in 3 years, at simple interest. What is the sum of money? Ans: sum of money p= 1800


  • kanjibhai
  • Feb 22, 2017

A sum of money becomes ` 2016 in 2 years and ` 2124 in 3 years, at simple interest. What is the sum of money?


  • kanjibhai
  • Feb 22, 2017

The ratio of 12th term to 15th term of a G.P. is 8 : 1. What is the common ratio of G.P?


  • Jas
  • Sep 01, 2016

Good answer


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Welcome to the NCERT Solutions for Class 11 Mathematics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 3 , Question 2: Find the 12th term of a G.P. whose 8th term is 192 and the common ratio is 2.....

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