This chapter belongs to a previous NCERT/CBSE curriculum and is not part of the current 2026-27 chapter list. Removed in 2022-23.
Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter The Solid State. This page offers a step-by-step solution to the specific question from Exercise 1, Question 6:
Classify the following solids in different categories based on the nature of intermolecular forces operating in them:
Potassium sulphate, tin, benzene, urea, ammonia, water, zinc sulphide, graphite, rubidium, argon, silicon carbide.
Classify the following solids in different categories based on the nature of intermolecular forces operating in them:
Potassium sulphate, tin, benzene, urea, ammonia, water, zinc sulphide, graphite, rubidium, argon, silicon carbide.
Potassium sulphate → Ionic bond is formed, wherein potassium loses electrons & sulphate gains electrons.
Tin → Tin can form two ions Sn 2+ or Sn 4+ now depending on what form it is in and what other element it is bonding with then only the type of bonding will be known.
Benzene → It comprises of sp2 hybridized carbon atoms which makes covalent bond with each other by mutual sharing and pairing of electrons.
Urea → Polar molecular solid and they mostly forms hydrogen bond with other atoms.
Ammonia → Covalently bonded polar compound formed by mutual sharing and pairing of electrons between nitrogen and three hydrogen atoms.
Water → Covalently bonded polar compound formed by mutual sharing of electrons between oxygen and hydrogen atoms.
Zinc sulphide → It exist in the form of crystals and makes coordination bond.
Graphite → It consist of carbon atoms and have covalent bond between them forming a 2-D (flat, planar etc.) network, which in itself is strong. These planes are then held together by London Forces, which are very weak.
Rubidium → Metallic bond is formed by rubidium because it is a metal. Metallic bond is hydride of covalent bond and ionic bond.
Argon → Non-polar molecular solid
Silicon carbide → Covalent or network solid
The reaction between A and B is first order with respect to A and zero order with respect to B. Fill in the blanks in the following table:
| Experiment |
A/ mol L - 1 |
B/ mol L - 1 |
Initial rate/mol L - 1 min - 1 |
| I | 0.1 | 0.1 |
2.0 × 10 - 2 |
| II | -- | 0.2 |
4.0 × 10 - 2 |
| III | 0.4 | 0.4 | -- |
| IV | -- | 0.2 |
2.0 × 10 - 2 |
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 6: Classify the following solids in different categories based on the nature of intermolecular forces o....
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Comments
I m still confused about tin
tin mostly forms metallic bond with other atoms & because it exist in two oxidation states ,the metallic bonds so formed will be of different nature depending upon the oxidation state of tin. zinc sulphide shows polymorphism & exists in the form of crystals where they form coordination bond with other atoms.Coordination bond is one of the type of covalent bond where the bond is formed by sharing of electrons coming from form same atom only i.e the electrons involved in bonding comes from one of the atom & not from both of the atoms .
Still confused about zinc sulphide and tin....lil more help plz!