Sucrose decomposes in acid solution into | Class 12 Chemistry Chapter Chemical Kinetics, Chemical Kinetics NCERT Solutions

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Academic session 2026-27, Chapter 3 in the current curriculum.

Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter Chemical Kinetics. This page offers a step-by-step solution to the specific question from Exercise 2, Question 25:

Sucrose decomposes in acid solution into glucose and fructose according to the first order rate law, with t1/2 = 3.00 hours. What fraction of sample of sucrose remains after 8 hours?

. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 25:

Sucrose decomposes in acid solution into glucose and fructose according to the first order rate law, with t1/2 = 3.00 hours. What fraction of sample of sucrose remains after 8 hours?

Answer:

For a first order reaction,

k = 2.303/t  Log  [R]º / [R]

It is given that, t1/2 = 3.00 hours

Therefore, k = 0.693 / t1/2

= 0.693 / 3  h-1

= 0.231 h - 1

Then, 0.231 h - 1 = 2.303 / 8h  Log  [R]º / [R]

Hence, the fraction of sample of sucrose that remains after 8 hours is 0.158.


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Chemical Kinetics.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Comments

  • Rohit
  • Jul 24, 2019

Antilog is very simple just split values Which comes then it becomes easy


  • Sanyam khattar
  • Aug 21, 2018

U will have to learn log table from 1 to 10 as log2=0.3010 log 3=0.4771 and so on so as the log of 2 is 0.3010 so antilog for 0.3010 will be 2 do this with all the no. Upto 10


  • Yashashwini
  • May 31, 2018

How will we know the antilog value?


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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 25: Sucrose decomposes in acid solution into glucose and fructose according to the first order rate law,....

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