This chapter belongs to a previous NCERT/CBSE curriculum and is not part of the current 2026-27 chapter list. Removed in 2022-23.
Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter The Solid State. This page offers a step-by-step solution to the specific question from Exercise 2, Question 16:
Analysis shows that nickel oxide has the formula Ni0.98 O1.00. What fractions of nickel exist as Ni2+and Ni3+ions?
. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.Analysis shows that nickel oxide has the formula Ni0.98 O1.00. What fractions of nickel exist as Ni2+and Ni3+ions?
The formula of nickel oxide is Ni0.98 O1.00.
Therefore, the ratio of the number of Ni atoms to the number of O atoms,
Ni : O = 0.98 : 1.00 = 98 : 100
Now, total charge on 100 O2 - ions = 100 × ( - 2) = - 200
Let the number of Ni2+ions be x.
So, the number of Ni3+ions is 98 - x.
Now, total charge on Ni2+ions = x(+2) = +2x
And, total charge on Ni3+ions = (98 - x)(+3) = 294 - 3x
Since, the compound is neutral, we can write: 2x+ (294 - 3x) + ( - 200) = 0
⇒ - x+ 94 = 0 ⇒ x= 94
Therefore, number of Ni2+ions = 94
And, number of Ni3+ions = 98 - 94 = 4
Hence, fraction of nickel that exists as Ni2+ = 94/98 = 0.959
And, fraction of nickel that exists as Ni3+ = 4/98 = 0.041
Alternatively, fraction of nickel that exists as Ni3+= 1 - 0.959 = 0.041
The reaction between A and B is first order with respect to A and zero order with respect to B. Fill in the blanks in the following table:
| Experiment |
A/ mol L - 1 |
B/ mol L - 1 |
Initial rate/mol L - 1 min - 1 |
| I | 0.1 | 0.1 |
2.0 × 10 - 2 |
| II | -- | 0.2 |
4.0 × 10 - 2 |
| III | 0.4 | 0.4 | -- |
| IV | -- | 0.2 |
2.0 × 10 - 2 |
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
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Welcome to the NCERT Solutions for Class 12 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 2 , Question 16: Analysis shows that nickel oxide has the formula Ni0.98 O1.00. What fractions of nickel exist as Ni2....
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Comments
Really helppul
Well explained
I was asking about only ni2+
I didn't really understand.How can it be 98-x for Ni3+ ions ???
Thanks very nice explaInation