The blades of a windmill sweep out a cir | Class 11 Physics Chapter Work Energy and Power, Work Energy and Power NCERT Solutions

Current NCERT chapter

Academic session 2026-27, Chapter 5 in the current curriculum.

Welcome to the NCERT Solutions for Class 11 Physics - Chapter Work Energy and Power. This page offers a step-by-step solution to the specific question from Exercise 1, Question 21:

The blades of a windmill sweep out a circle of area A. (a) If the wind flows at a velocity v perpendicular to the circle, what is the mass of the air passing through it in time t?(b) What is the kinetic energy of the air? (c) Assume that the windmill converts 25% of the wind's energy into electrical energy, and that A = 30 m2, v = 36 km/h and the density of air is 1.2 kg m-3. What is the electrical power produced?

. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 21:

The blades of a windmill sweep out a circle of area A. (a) If the wind flows at a velocity v perpendicular to the circle, what is the mass of the air passing through it in time t?(b) What is the kinetic energy of the air? (c) Assume that the windmill converts 25% of the wind's energy into electrical energy, and that A = 30 m2, v = 36 km/h and the density of air is 1.2 kg m-3. What is the electrical power produced?

Answer:

Area of the circle swept by the windmill = A

Velocity of the wind = v

Density of air = p

(a) Volume of the wind flowing through the windmill per sec = Av

Mass of the wind flowing through the windmill per sec = pAv

Mass m, of the wind flowing through the windmill in time t = pAvt

 

(b) Kinetic energy of air  =  ½ mv2

= ½ (pAvt)v2  =  ½ pAv3t

 

(c) Area of the circle swept by the windmill = A = 30 m2

Velocity of the wind = v= 36 km/h

Density of air,  p = 1.2 kg m-3

Electric energy produced = 25% of the wind energy

= 25/100 x Kinetic energy of air

= 1/8 pAv3t

Electrical Power  = Electical energy / time

= 1/8 pAv3t / t = 1/8 pAv3

= 1/8 x 1.2 x 30 x 103

= 4.5 x 103 w

= 4.5 kW


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Work Energy and Power.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Comments

  • Payel Shit
  • Sep 25, 2018

What will be the mechanical power???


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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 21: The blades of a windmill sweep out a circle of area A. (a) If the wind flows at a velocity v perpend....

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