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Academic session 2026-27, Chapter 6 in the current curriculum.
Welcome to the NCERT Solutions for Class 11 Physics - Chapter System of Particles and Rotational Motion. This page offers a step-by-step solution to the specific question from Exercise 1, Question 19:
A hoop of radius 2 m weighs 100 kg. It rolls along a horizontal floor so that its centre of mass has a speed of 20 cm/s. How much work has to be done to stop it?
. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.A hoop of radius 2 m weighs 100 kg. It rolls along a horizontal floor so that its centre of mass has a speed of 20 cm/s. How much work has to be done to stop it?
Radius of the hoop, r = 2 m
Mass of the hoop, m = 100 kg
Velocity of the hoop, v = 20 cm/s = 0.2 m/s
Total energy of the hoop = Translational KE + Rotational KE
Er = 1/2 mv2 + 1/2 I ω2
Moment of inertia of the hoop about its centre, I = mr2
Er = 1/2 mv2 + 1/2 (mr2) ω2
But we have the relation, v = rω
∴ Er = 1/2 mv2 + 1/2 mr2 ω2
∴ Er = 1/2 mv2 + 1/2 mv2
∴ Er = mv2
The work required to be done for stopping the hoop is equal to the total energy of the hoop.
∴Required work to be done, W = mv2 = 100 × (0.2)2 = 4 J
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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 19: A hoop of radius 2 m weighs 100 kg. It rolls along a horizontal floor so that its centre of mass has....
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Very nice answer