Percentage Calculator
Calculate percentage from obtained marks and total marks.
Academic session 2026-27, Chapter 7 in the current curriculum.
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Redox Reactions. This page offers a step-by-step solution to the specific question from Exercise 1, Question 11:
Whenever a reaction between an oxidising agent and a reducing agent is carried out, a compound of lower oxidation state is formed if the reducing agent is in excess and a compound of higher oxidation state is formed if the oxidising agent is in excess. Justify this statement giving three illustrations.
. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.Whenever a reaction between an oxidising agent and a reducing agent is carried out, a compound of lower oxidation state is formed if the reducing agent is in excess and a compound of higher oxidation state is formed if the oxidising agent is in excess. Justify this statement giving three illustrations.
Whenever a reaction between an oxidising agent and a reducing agent is carried out, a compound of lower oxidation state is formed if the reducing agent is in excess and a compound of higher oxidation state is formed if the oxidising agent is in excess. This can be illustrated as follows:
(i) P4 and F2 are reducing and oxidising agents respectively.
If an excess of P4 is treated with F2, then PF3 will be produced, wherein the oxidation number (O.N.) of P is +3.
P4 (excess) + F2 → P+3F3
However, if P4 is treated with an excess of F2, then PF5 will be produced, wherein the O.N. of P is +5.
P4 + F2 (excess) → P+5F5
(ii) K acts as a reducing agent, whereas O2 is an oxidising agent. If an excess of K reacts with O2, then K2O will be formed, wherein the O.N. of O is -2.
4K (excess) + O2 → 2K2O-2
However, if K reacts with an excess of O2, then K2O2 will be formed, wherein the O.N. of O is -1.
2K + O2 (excess) → K2O-12
(iii) C is a reducing agent, while O2 acts as an oxidising agent.
If an excess of C is burnt in the presence of insufficient amount of O2, then CO will be produced, wherein the O.N. of C is +2.
C (excess) + O2 → C+2O
On the other hand, if C is burnt in an excess of O2, then CO2 will be produced, wherein the O.N. of C is +4.
C + O2 (excess) → C+4O2
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
Stay updated with our latest educational content and study tips
All businesses are gathering information on customers, products, employees, and expenditures, and someone must make decisions based on the data. That individual is the data analyst. Unlike many career changers imagine, the job is open to a broader cross-section of the population than a typical career change. A lot of working analysts trained in commerce, … Read more
Read MoreAre often purchased, talked and planned as being a replacement for another. They aren’t. One safeguards your family’s income in your absence and the other safeguards your family’s savings in the event that someone becomes ill. An examination of what they do, what they do not do, and why they are missing it when one … Read more
Read MorePay upfront, or pay off less and over time? The truth depends on four factors most consumers will never compare at the same time: the interest rate on the house loan, the interest rate on the savings account, the rate of home price appreciation, and the cost of renting the home until you actually buy … Read more
Read MoreThirty is when the question starts to get raised and you’re able to do something because you know you have the experience—you know you have the responsibility. Here are some ways to consider the choice based on a realistic assessment without idealizing either aspect. Restlessness is one of those things that appears in your early … Read more
Read MoreCalculate percentage from obtained marks and total marks.
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 11: Whenever a reaction between an oxidising agent and a reducing agent is carried out, a compound of lo....
Fresh educational articles and updates.
Most-read articles from SaralStudy.
Fast access to frequently used study resources.
Recently viewed articles based on SaralStudy activity.
Add Comment