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Academic session 2026-27, Chapter 4 in the current curriculum.
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Chemical Bonding and Molecular Structure. This page offers a step-by-step solution to the specific question from Exercise 1, Question 25:
Describe the change in hybridisation (if any) of the Al atom in the following reaction.

Describe the change in hybridisation (if any) of the Al atom in the following reaction.

Here in the given equation AlCl3 , Al is shifting its hybridization state from sp2 to sp3 because if we see the electronic configuration of Al it is [Ne] 3s2 3p1, i.e it has 3 electrons in its valence shell during ground state.In its excited state its one s orbital & two p orbitals will take part in hybridization to form sp2 hybrid orbital.
The orbital picture of aluminium in the excited state can be represented as:

Now according to the given reaction the product formed AlCl4- , will only be formed if its 3pz orbital is also filled by one electron in its excited state to form a sp3 hybrid orbital .therefore Al will shift its hybridization form sp2 to sp3 to form a tetrahedral shape
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 25: Describe the change in hybridisation (if any) of the Al atom in the following reaction.....
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Comments
1/2(3+4+1)=4=sp3
How can you find the hybridisation of alcl4- by using the shortcut formula? 1/2(v+M-c+A)= 1/2(3+4-1) =3=sp2 hybridisation?
Change
So what is the final answer. .Change or no change