Describe the hybridisation in case of PC | Class 11 Chemistry Chapter Chemical Bonding and Molecular Structure, Chemical Bonding and Molecular Structure NCERT Solutions

Current NCERT chapter

Academic session 2026-27, Chapter 4 in the current curriculum.

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Chemical Bonding and Molecular Structure. This page offers a step-by-step solution to the specific question from Exercise 1, Question 38:

Describe the hybridisation in case of PCl5. Why are the axial bonds longer as compared to equatorial bonds?

. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 38:

Describe the hybridisation in case of PCl5. Why are the axial bonds longer as compared to equatorial bonds?

Answer:

Atomic number of Phosphorous is 15.

The Ground state configuration is

& the excited state configuration is

The 5 electrons present in valence shell form bond pairs with the electrons of five chlorine atoms. Phosphorus atom is sp3d hybridized in the excited state.

PCl5

The geometry of PCl5 is trigonal bipyramidal .The P atom lies in the centre of an equatorial triangle & three P-Cl bonds (equatorial bonds) are directed towards its three corners with 120° bond angle. The remaining two P-Cl bonds (axial bonds) lie above & below the plane of the triangle at bond angle 90° .

 

The axial bonds are longer than equatorial bonds because the axial Cl atoms suffer from more repulsion then the equatorial Cl atoms,as a result the axial Cl atoms tries to reside far away from the equatorial Cl atoms, & hence axial bond are longer than equatorial bonds.


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Chemical Bonding and Molecular Structure.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Comments

  • Gandheswari
  • Sep 24, 2019

Thanku


  • haha
  • Sep 13, 2019

wrong config given... please correct


  • Prakash Pramanik
  • Nov 24, 2018

Orbital diagram of P atom


  • Prakash Pramanik
  • Nov 24, 2018

Formation of PCl5 molecule class11th


  • Vijay Hemanth
  • Sep 21, 2018

Define BMO and ABMO? How is it used to calculate bond order of the molecule???


  • Adarsh Kumar singh
  • Apr 20, 2018

Answer is right but electronic configuration is wrong because 3P have 3 degerated orbital and 3D have 5.


  • Bijay
  • Oct 20, 2017

Answer is good but it electroni configuration is give wrong


  • pankaj Sharma
  • Oct 12, 2017

Nice working with this answered


  • BHAVEY
  • Mar 10, 2016

exelent...


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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 38: Describe the hybridisation in case of PCl5. Why are the axial bonds longer as compared to equatorial....

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