Calculate the oxidation number of sulphu | Class 11 Chemistry Chapter Redox Reactions, Redox Reactions NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Redox Reactions. This page offers a step-by-step solution to the specific question from Exercise 1, Question 5: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 5:

Calculate the oxidation number of sulphur, chromium and nitrogen in H2SO5, Cr2O2- 7 and NO 3. Suggest structure of these compounds. Count for the fallacy.

Answer:

(a) H2SO5

Let assume oxidation number of S is x.

We know that,

Oxidation number of H = +1

Oxidation number of O = -2

Then we have

2(+1) + (x) + 5 (-2) = 0

⇒ 2 + x - 10 = 0

⇒ x  =  +8

However, the O.N. of S cannot be +8. S has six valence electrons. Therefore, the O.N. of S cannot be more than +6. The structure of H2SO5 is shown as follows:

Now , 2(+1) + 1(x) + 3(-2)  + 2 (-1) = 0

⇒ 2 + x - 6 -2 = 0

⇒ x  =  +6

Therefore, the O.N. of S is +6.

 

(b) Cr2O2-7

Let assume oxidation number of Cr is x.

We know that,

Oxidation number of O = -2

Then we have

 2(x) + 7 (-2) =  -2

⇒ 2x  -14  = -2

⇒ 2x   =  +12

x  = +6

Here, there is no fallacy about the O.N. of Cr in Cr2O72-

The structure of Cr2O72- is shown as follows: 

Here, each of the two Cr atoms exhibits the O.N. of +6. 

 

(c) NO3-

Let assume oxidation number of N is x.

We know that,

Oxidation number of O = -2

Then we have

1(x) + 3 (-2) =  -1

⇒ x  - 6 = -1

⇒ x   =  +5

Here, there is no fallacy about the O.N. of N in NO3-

The structure of  NO3is shown as follows:

The N atom exhibits the O.N. of +5. 

 


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Redox Reactions.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 5: Calculate the oxidation number of sulphur, chromium and nitrogen in H2SO5, Cr2O2- 7 and NO– 3.....