If the speed of light is 3.0 × 108 | Class 11 Chemistry Chapter Some Basic Concepts of Chemistry, Some Basic Concepts of Chemistry NCERT Solutions

Current NCERT chapter

Academic session 2026-27, Chapter 1 in the current curriculum.

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Some Basic Concepts of Chemistry. This page offers a step-by-step solution to the specific question from Exercise 1, Question 22:

If the speed of light is 3.0 × 108 ms–1, calculate the distance covered by light in 2.00 ns.

. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 22:

If the speed of light is 3.0 × 108 ms–1, calculate the distance covered by light in 2.00 ns.

Answer:

According to the question:

Time taken to cover the distance = 2.00 ns

= 2.00 × 10–9 s

Speed of light = 3.0 × 108 ms–1

We know speed = distance/time

Or distance = speed x time

Therefore   Distance travelled by light in 2.00 ns

= Speed of light × Time taken

= (3.0 × 108 ms –1) (2.00 × 10–9 s)

= 6.00 × 10–1 m

= 0.600 m


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Some Basic Concepts of Chemistry.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Comments

  • Shreya
  • May 10, 2020

Thanks for the solution but what is na here.


  • Ujjwal Chaurasia
  • Nov 16, 2019

Thanks for confirmation


  • Shahtab
  • Oct 03, 2019

What is ns here?


  • Umar
  • Aug 08, 2019

Thanks alot


  • Aman Gupta
  • Aug 05, 2019

Thanks


  • Teena
  • May 05, 2019

Wow


  • Prakhar Crazy
  • Aug 04, 2018

Thanks


  • Sahil
  • Jun 14, 2018

Thnks for sugesation


  • Navneet singh
  • May 08, 2018

thanks alot


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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 22: If the speed of light is 3.0 × 108 ms–1, calculate the distance covered by light in 2.00....

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