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Academic session 2026-27, Chapter 1 in the current curriculum.
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Some Basic Concepts of Chemistry. This page offers a step-by-step solution to the specific question from Exercise 1, Question 32:
Use the data given in the following table to calculate the molar mass of naturally occurring argon isotopes:
|
Isotope |
Isotopic molar mass |
Abundance |
|
36Ar |
35.96755 gmol–1 |
0.337% |
|
38Ar |
37.96272 gmol–1 |
0.063% |
|
40Ar |
39.9624 gmol–1 |
99.600% |
Use the data given in the following table to calculate the molar mass of naturally occurring argon isotopes:
|
Isotope |
Isotopic molar mass |
Abundance |
|
36Ar |
35.96755 gmol–1 |
0.337% |
|
38Ar |
37.96272 gmol–1 |
0.063% |
|
40Ar |
39.9624 gmol–1 |
99.600% |
Molar mass of argon =
Atomic mass of 36Ar = 35.96755 & abundance = 0.337
Or
total atomic mass of 36Ar = 35.96755 * 0.337= 0.121g/mol
Atomic mass of 38Ar = 37.96272 & abundance = 0.063
Or
total atomic mass of 38Ar = 37.96272 * 0.063= 0.024g/mol
Atomic mass of 40Ar =39.9624 & abundance = 99.600
Or
total atomic mass of 40Ar = 39.9624 * 99.600= 39.802g/mol
Therefore molar mass of argon = total mass of 36Ar+ total mass of 38Ar + atomic mass of 40Ar
= 0.121 + 0.024 + 39.802= 39.947 g/mol
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 32: Use the data given in the following table to calculate the molar mass of naturally occurring argon i....
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