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Academic session 2026-27, Chapter 1 in the current curriculum.
Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Some Basic Concepts of Chemistry. This page offers a step-by-step solution to the specific question from Exercise 1, Question 6:
Calculate the concentration of nitric acid in moles per litre in a sample which has a density, 1.41 g mL–1 and the mass per cent of nitric acid in it being 69%.
. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.Calculate the concentration of nitric acid in moles per litre in a sample which has a density, 1.41 g mL–1 and the mass per cent of nitric acid in it being 69%.
Mass of nitric acid solution = 69 g (because 69% means 69 g dissolved in 100 ml of solvent)
Density of nitric acid solution = 1.41 g/ml
Volume of nitric acid solution = mass/density= 100/1.41 = 70.92 ml
No of moles of nitric acid = mass of nitric acid/molar mass of nitric acid=69/63= 1.09
Volume of the solution = 70.92
Molarity of the solution = moles of nitric acid/volume of solution in litres
= 1.09*1000/70.92= 15.37 moles/liter
∴Concentration of nitric acid = 15.37 mol/L
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 6: Calculate the concentration of nitric acid in moles per litre in a sample which has a density, 1.41 ....
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