Academic session 2026-27, Chapter 8 in the current curriculum.
Welcome to the NCERT Solutions for Class 11 Mathematics - Chapter Sequence and Series. This page offers a step-by-step solution to the specific question from Exercise 5, Question 4:
Find the sum of all numbers between 200 and 400 which are divisible by 7.
. With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.Find the sum of all numbers between 200 and 400 which are divisible by 7.
The numbers lying between 200 and 400, which are divisible by 7, are
203, 210, 217, … 399
∴First term, a = 203
Last term, l = 399
Common difference, d = 7
Let the number of terms of the A.P. be n.
∴ an = 399 = a + (n –1) d
⇒ 399 = 203 + (n –1) 7
⇒ 7 (n –1) = 196
⇒ n –1 = 28
⇒ n = 29
Thus, the required sum is 8729.
NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:
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Welcome to the NCERT Solutions for Class 11 Mathematics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 5 , Question 4: Find the sum of all numbers between 200 and 400 which are divisible by 7.....
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Comments
Good
ummma thank you
But how I know that first no. Is 203
thank you great elucidation
wonderfull explanation
Thank you for your help
Good solution.
Thanks for the explanation
it was a wonderful explanation
Good explanation