From a rifle of mass 4 kg, a bullet of mass 50 g is fired with an initial velocity of 35 m s-1. Calculate the initial recoil velocity of the rifle.
Mass of the rifle, m1 = 4 kg
Mass of the bullet, m2 = 50g = 0.05 kg
Recoil velocity of the rifle = v1
Bullet is fired with an initial velocity, v2 = 35 m/s
Total mass = m1 + m2 = 4 + 0.05 = 4.05 kg
Since the system was at rest , velocity (v) = 0
Momentum ( before firing ) = mass x velocity = ( m1 + m2 )v = ( 4.05 ) 0 = 0 kg m/s
Total momentum = momentum of bullet + momentum of rifle = m1 v1 + m2 v2
= 0.05 x 35 + 4 x v2 = 7/4 + 4 v2
Since the total momentum remain conserved
Total momentum before firing = Total momentum after firing
0 = 7/4 + 4 v2
4 v2 = - 7/4
v2 = - 7/16
v2 = -04375 m/s
Thus , the recoil velocity of the pistol is -0.4375 m/s .
The negative sign of velocity means that the rifle will recoil in the opposite direction of the bullet.
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Akhtar, Kiran and Rahul were riding in a motorcar that was moving with a high velocity on an expressway when an insect hit the windshield and got stuck on the windscreen. Akhtar and Kiran started pondering over the situation. Kiran suggested that the insect suffered a greater change in momentum as compared to the change in momentum of the motorcar (because the change in the velocity of the insect was much more than that of the motorcar). Akhtar said that since the motorcar was moving with a larger velocity, it exerted a larger force on the insect. And as a result the insect died. Rahul while putting an entirely new explanation said that both the motorcar and the insect experienced the same force and a change in their momentum. Comment on these suggestions
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