Class 11 Physics - Chapter Waves NCERT Solutions | A stone dropped from the top of a tower

Welcome to the NCERT Solutions for Class 11th Physics - Chapter Waves. This page offers a step-by-step solution to the specific question from Exercise 1, Question 2: a stone dropped from the top of a tower of height....
Question 2

A stone dropped from the top of a tower of height 300 m high splashes into the water of a pond near the base of the tower. When is the splash heard at the top given that the speed of sound in air is 340 m s-1? (g= 9.8 m s-2)

Answer

Height of the tower, s = 300 m

Initial velocity of the stone, u = 0

Acceleration, a = g = 9.8 m/s2

Speed of sound in air = 340 m/s

The time (t1) taken by the stone to strike the water in the pond can be calculated using the second equation of motion, as:

s  =  ut1  + 1/2 gt21

300 =  0 + 1/2 x 9.8 x t12

∴ t=  underroot [(300 x 2)  /  9.8]

= 7.82 s

Time taken by the sound to reach the top of the tower, t2  =  300/340  = 0.88 s

Therefore, the time after which the splash is heard,  t  =   t1 +  t2

= 7.82 + 0.88 = 8.7 s

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