Class 11 Physics - Chapter Unit and measurment NCERT Solutions | Fill in the blanks (a) The volume of

Welcome to the NCERT Solutions for Class 11th Physics - Chapter Unit and measurment. This page offers a step-by-step solution to the specific question from Excercise ".$ex_no." , Question 1: fill in the blanks a the volume of a cube of....
Question 1

Fill in the blanks

(a) The volume of a cube of side 1 cm is equal to.....m3

(b) The surface area of a solid cylinder of radius 2.0 cm and height 10.0 cm is equal to ... (mm)2

(c) A vehicle moving with a speed of 18 km h–1covers....m in 1 s

(d) The relative density of lead is 11.3. Its density is ....g cm–3 or . ...kg m–3.

Answer

a)

Length of edge  = 1 cm 
Volume of the cube = 1 cm3

But, 

1 cm3 = 1 cm × 1 cm × 1 cm = (1/100)m x (1/100)m x (1/100)m 
∴1 cm3 = 10–6 m3

Hence, the volume of a cube of side 1 cm is equal to 10–6 m3.

 

(b) The total surface area of a cylinder of radius r and height h is S = 2πr (r + h).

Given that, r = 2 cm = 2 × 1 cm = 2 × 10 mm = 20 mm

h = 10 cm = 10 × 10 mm = 100 mm = 15072 = 1.5 × 104 mm2

 

(c) Using the conversion, 1 km/h = 5/18 m/s

18km/h =  18 x  5/18  =  5 m/s

Therefore, distance can be obtained using the relation:

Distance = Speed × Time

= 5 × 1 = 5 m

Hence, the vehicle covers 5 m in 1 s.

 

(d) Relative density of a substance is given by the relation,

Relative density = Density of Substance /  Density of Water

Density of water = 1 g/cm3

Again, 1g = 1/1000 kg

1 cm3 = 10–6 m3

1 g/cm3 = 10-3 / 10-6 kg/m3 = 103 kg/m3

∴ 11.3 g/cm3 = 11.3 × 103 kg/m3

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