A solution is obtained by mixing 300 g of 25% solution and 400 g of 40% solution by mass. Calculate the mass percentage of the resulting solution.
According to question,
300g of 25% solution contains solute = (300 x 25) / 100 = 75g
&
400g of 40% solution contains solute = (400 x 40) / 100 = 160g
Total solute = 75 + 160 = 235g
As given in the question, total solution =300 + 400 = 700g
Percentage of solute in the final solution = (235 x100) / 700 = 33.57%
Percentage of water in the final solution = 100 - 33.5 = 65.43%
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(ii) Potassium tetracyanonickelate(II)
(iii) Tris(ethane-1,2-diamine) chromium(III) chloride
(iv) Amminebromidochloridonitrito-N-platinate(II)
(v) Dichloridobis(ethane-1,2-diamine)platinum(IV) nitrate
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(ii) Write IUPAC names of all the isomers.
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(i) α-Methoxypropionaldehyde
(ii) 3-Hydroxybutanal
(iii) 2-Hydroxycyclopentane carbaldehyde
(iv) 4-Oxopentanal
(v) Di-sec-butyl ketone
(vi) 4-Fluoroacetophenone
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(v) (vi) PhCOPh
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log k = 14.34 - 1.25 x 104 K/T
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(iv) Aniline to 2,4,6-tribromofluorobenzene
(v) Benzyl chloride to 2-phenylethanamine
(vi) Chlorobenzene to p-chloroaniline
(vii) Aniline to p-bromoaniline
(viii) Benzamide to toluene
(ix) Aniline to benzyl alcohol.
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Thnx sir
But finally percentage is 64.5%
Please correct that Percentage of H2O in final solution is 66.5 % not 65.5 %
Please correct that Percentage of H2O in final solution is 66.5 % not 65.5 %
Thanks
thnx sir
Thanks sir for this answer, this answer will help me a lot
Thanks
If percentage composition in terms of mass is asked
If percentage composition in terms of mass is asked