Class 11 Physics - Chapter Oscillations NCERT Solutions | A circular disc of mass 10 kg is suspend

Welcome to the NCERT Solutions for Class 11th Physics - Chapter Oscillations. This page offers a step-by-step solution to the specific question from Exercise 1, Question 23: a circular disc of mass 10 kg is suspended by a wi....
Question 23

A circular disc of mass 10 kg is suspended by a wire attached to its centre. The wire is twisted by rotating the disc and released. The period of torsional oscillations is found to be 1.5 s. The radius of the disc is 15 cm. Determine the torsional spring constant of the wire.

(Torsional spring constant α is defined by the relation J = -α ø, where J is the restoring couple and ø¸ the angle of twist).

Answer

Mass of the circular disc, m = 10 kg

Radius of the disc, r = 15 cm = 0.15 m

The torsional oscillations of the disc has a time period, T = 1.5 s

The moment of inertia of the disc is:

l  =  1/2 mr2

= 1/2 x 10 x (0.15)2

= 0.1125 kg m2

Time period,  T  = 2π underroot 1 / α

α is the torsional constant.

α = 4 π2 l / T2

= 4 x π2 x 0.1125  / (1.5)2

= 1.972 Nm/rad

Hence, the torsional spring constant of the wire is 1.972 Nm rad-1.

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