Class 11 Physics - Chapter Mechanical Properties of Fluids NCERT Solutions | In problem 10.9, if 15.0 cm of water and

Welcome to the NCERT Solutions for Class 11th Physics - Chapter Mechanical Properties of Fluids. This page offers a step-by-step solution to the specific question from Exercise 1, Question 10: in problem 10 9 if 15 0 cm of water and spirit ea....
Question 10

In problem 10.9, if 15.0 cm of water and spirit each are further poured into the respective arms of the tube, what is the difference in the levels of mercury in the two arms? (Specific gravity of mercury = 13.6)

Answer

Height of the water column, h1 = 10 + 15 = 25 cm

Height of the spirit column, h2 = 12.5 + 15 = 27.5 cm

Density of water, p1 = 1 g cm-3

Density of spirit, p2 = 0.8 g cm-3

Density of mercury = 13.6 g cm-3

Let h be the difference between the levels of mercury in the two arms.

Pressure exerted by height h, of the mercury column:

= hpg

= h × 13.6g … (i)

Difference between the pressures exerted by water and spirit:

= h1p1g

= g(25 × 1 -  27.5 × 0.8) = 3g … (ii)

Equating equations (i) and (ii), we get:

13.6 hg = 3g

h = 0.220588 ≈ 0.221 cm

Hence, the difference between the levels of mercury in the two arms is 0.221 cm.

More Questions From Class 11 Physics - Chapter Mechanical Properties of Fluids

Popular Questions of Class 11 Physics

Recently Viewed Questions of Class 11 Physics

Write a Comment: