Class 12 Physics - Chapter Magnetism and Matter NCERT Solutions | A short bar magnet of magnetic moment m

Welcome to the NCERT Solutions for Class 12th Physics - Chapter Magnetism and Matter. This page offers a step-by-step solution to the specific question from Exercise 1, Question 4: a short bar magnet of magnetic moment m 0 32 jt....
Question 4

A short bar magnet of magnetic moment m = 0.32 JT-1is placed in a uniform magnetic field of 0.15 T. If the bar is free to rotate in the plane of the field, which orientation would correspond to its (a) stable, and (b) unstable equilibrium? What is the potential energy of the magnet in each case?

Answer

Moment of the bar magnet, M= 0.32 J T-1

External magnetic field, B= 0.15 T

(a)The bar magnet is aligned along the magnetic field. This system is considered as being in stable equilibrium. Hence, the angle θ, between the bar magnet and the magnetic field is 0°.

Potential energy of the system = - MB cosθ
=-0.32 x 0.15cos0°
=4.8 x 10-2 J


(b)The bar magnet is oriented 180°to the magnetic field. Hence, it is in unstable equilibrium.

θ = 180°

Potential energy = - MBcosθ

=-0.32 x 0.15cos180°
=4.8 x 10-2 J

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