Class 12 Physics - Chapter Electrostatic Potential and Capacitance NCERT Solutions | Two charges 5 x 10-8 C and -3 x 10-8 C a

Welcome to the NCERT Solutions for Class 12th Physics - Chapter Electrostatic Potential and Capacitance. This page offers a step-by-step solution to the specific question from Exercise 1, Question 1: two charges 5 x 10 8 c and 3 x 10 8 c are located....
Question 1

Two charges 5 x 10-8 C and -3 x 10-8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

 

Answer

There are two charges,

Distance between the two charges, d = 16 cm = 0.16 m

Consider a point P on the line joining the two charges, as shown in the given figure.

 

r = Distance of point P from charge q1

Let the electric potential (V) at point P be zero.

Potential at point P is the sum of potentials caused by charges q1 and q2 respectively.

Where, = Permittivity of free space

For V = 0, equation (i) reduces to

Therefore, the potential is zero at a distance of 10 cm from the positive charge between the charges.

Suppose point P is outside the system of two charges at a distance s from the negative charge, where potential is zero,

as shown in the following figure.

For this arrangement, potential is given by,

For V = 0, equation (ii) reduces to

Therefore, the potential is zero at a distance of 40 cm from the positive charge outside the system of charges.

More Questions From Class 12 Physics - Chapter Electrostatic Potential and Capacitance

Popular Questions of Class 12 Physics

Recently Viewed Questions of Class 12 Physics

2 Comment(s) on this Question

Write a Comment: