A system has two charges qA = 2.5 × 10−7 C and qB = −2.5 × 10−7 C located at points A: (0, 0, − 15 cm) and B: (0, 0, + 15 cm), respectively. What are the total charge and electric dipole moment of the system?
According to the figure given below both the charges can be located in a coordinate frame of reference.
At A, amount of charge, qA = 2.5 × 10−7C (Given)
At B, amount of charge, qB = −2.5 × 10−7 C (Given)
Total charge of the system,
q = qA + qB = 2.5 × 10-7 C − 2.5 × 10−7 C = 0
Distance between two charges at points A and B,
d = 15 + 15 = 30 cm = 0.3 m
Electric dipole moment of the system is given by,
p = qA × d = qB × d = 2.5 × 10−7 × 0.3 = 7.5 × 10−8 C m along positive z-axis
Therefore, the electric dipole moment of the system is 7.5 × 10−8 C m along positive z−axis.
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(b) Is there a transfer of mass from wool to polythene?
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A conducting sphere of radius 10 cm has an unknown charge. If the electric field 20 cm from the centre of the sphere is 1.5 × 103 N/C and points radially inward, what is the net charge on the sphere?
A point charge of 2.0 μC is at the centre of a cubic Gaussian surface 9.0 cm on edge. What is the net electric flux through the surface?
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(a) What is the distance between the two spheres?
(b) What is the force on the second sphere due to the first?
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(a) What is the electric field at the midpoint O of the line AB joining the two charges?
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(b) What is the total electric flux leaving the surface of the sphere?
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Would you expect a greater or smaller dip angle in Britain?
(c) If you made a map of magnetic field lines at Melbourne in Australia, would the lines seem to go into the ground or come out of the ground?
(d) In which direction would a compass free to move in the vertical plane point to, if located right on the geomagnetic north or south pole?
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(c) Is Kirchhoff’s first rule (junction rule) valid at each plate of the capacitor? Explain.
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(a) remains constant for all frequencies.
(b) is high at high and low frequencies and constant in the middle frequency range.
(c) is low at high and low frequencies and constant at mid frequencies.
(d) None of the above.
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it is simple 15-(-15)=30 cm answer is 0.03 m
how to find distance in graph points?????????????????????????
Exactly chaitanya
The dipole must be along negative z axis