Class 12 Physics - Chapter Dual Nature Of Radiation And Matter NCERT Solutions | What is the (a) momentum, (b) spee

Welcome to the NCERT Solutions for Class 12th Physics - Chapter Dual Nature Of Radiation And Matter. This page offers a step-by-step solution to the specific question from Excercise ".$ex_no." , Question 13: what is the a momentum b speed and....
Question 13

What is the

(a) momentum,

(b) speed, and

(c) de Broglie wavelength of an electron with kinetic energy of 120 eV.

Answer

Kinetic energy of the electron, Ek = 120 eV

Planck’s constant, h = 6.6 × 10−34 Js

Mass of an electron, m = 9.1 × 10−31 kg

Charge on an electron, e = 1.6 × 10−19 C

(a) For the electron, we can write the relation for kinetic energy as: Ek = 1/2 mv2

Where, v = Speed of the electron

Momentum of the electron, p = mv = 9.1 × 10−31 × 6.496 × 106 = 5.91 × 10−24 kg ms−1

Therefore, the momentum of the electron is 5.91 × 10−24 kg m s−1 .

 

(b) Speed of the electron, v = 6.496 × 106 m/s

 

(c) De Broglie wavelength of an electron having a momentum p, is given as: λ = h/p = 6.6 x 10-34 / 5.91 x 10-24 = 1.116 x 10-10 m = 0.112 nm

Therefore, the de Broglie wavelength of the electron is 0.112 nm.

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