Class 11 Mathematics - Chapter Sequence and Series NCERT Solutions | If 

Welcome to the NCERT Solutions for Class 11th Mathematics - Chapter Sequence and Series. This page offers a step-by-step solution to the specific question from Excercise ".$ex_no." , Question 13: if nbsp....
Question 13

If fraction numerator a space plus b x over denominator a space minus space b x end fraction space equals space fraction numerator b space plus space c x over denominator b space minus space c x end fraction space equals space fraction numerator c space plus space d x over denominator c space minus d x end fraction space open parentheses x space not equal to 0 close parentheses

Answer

It is given that,

fraction numerator a space plus space b x over denominator a space minus b x end fraction space equals space fraction numerator b space plus space c x over denominator b space minus c x end fraction
rightwards double arrow space open parentheses a space plus space b x close parentheses open parentheses b minus c x close parentheses space equals space open parentheses b plus c x close parentheses open parentheses a minus b x close parentheses
rightwards double arrow a b space minus space a c x space plus space b squared x space minus space b c x squared space equals space a b space minus space b squared x space plus space a c x space minus space b c x squared
rightwards double arrow 2 b squared x space equals space 2 a c x
rightwards double arrow b squared space equals space a c
rightwards double arrow b over a space equals space c over b space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space... left parenthesis 1 right parenthesis
A l s o comma space fraction numerator b plus c x over denominator b minus c x end fraction space equals space fraction numerator c space plus d x over denominator c space minus d x end fraction space
rightwards double arrow open parentheses b plus c x close parentheses open parentheses c minus d x close parentheses space equals space open parentheses b minus c x close parentheses open parentheses c plus d x close parentheses
rightwards double arrow b c space minus space b d x space plus space c squared x space minus space c d x squared space equals space b c space plus space b d x space minus space c squared x space minus space c d x squared
rightwards double arrow 2 c squared x space equals space 2 b d x
rightwards double arrow c squared space equals space b d
rightwards double arrow c over d space equals space d over c space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space... left parenthesis 2 right parenthesis

From (1) and (2), we obtain

b over a space equals space c over b space equals d over c

Thus, abc, and d are in G.P.

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