Class 11 Mathematics - Chapter Sequence and Series NCERT Solutions | Find the sum of all numbers between 200

Welcome to the NCERT Solutions for Class 11th Mathematics - Chapter Sequence and Series. This page offers a step-by-step solution to the specific question from Exercise 5, Question 4: find the sum of all numbers between 200 and 400 wh....
Question 4

Find the sum of all numbers between 200 and 400 which are divisible by 7.

Answer

The numbers lying between 200 and 400, which are divisible by 7, are

203, 210, 217, ­­­­­­­­… 399

∴First term, a = 203

Last term, l = 399

Common difference, d = 7

Let the number of terms of the A.P. be n.

∴ an = 399 = a + (n –1) d

⇒ 399 = 203 + (n –1) 7

⇒ 7 (n –1) = 196

⇒ n –1 = 28

⇒ n = 29

therefore space S subscript 29 space equals space 29 over 2 space open parentheses 203 space plus space 399 close parentheses
space space space space space space space space space space space space space equals space 29 over 2 space open parentheses 602 close parentheses
space space space space space space space space space space space space space equals space open parentheses 29 close parentheses open parentheses 301 close parentheses
space space space space space space space space space space space space space equals space 8729

Thus, the required sum is 8729.

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