Class 11 Mathematics - Chapter Sequence and Series NCERT Solutions | Find a G.P. for which sum of the first t

Welcome to the NCERT Solutions for Class 11th Mathematics - Chapter Sequence and Series. This page offers a step-by-step solution to the specific question from Excercise ".$ex_no." , Question 16: find a g p for which sum of the first two terms i....
Question 16

Find a G.P. for which sum of the first two terms is –4 and the fifth term is 4 times the third term.

Answer

Let a be the first term and r be the common ratio of the G.P.

According to the given conditions,

S subscript 2 space equals space minus 4 space equals space fraction numerator a open parentheses 1 minus r squared close parentheses over denominator 1 minus r end fraction space space space space space space space space space... left parenthesis 1 right parenthesis
a subscript 5 space equals space 4 space cross times space a subscript 3
a r to the power of 4 space equals space 4 a r squared
rightwards double arrow r squared space equals space 4
therefore space r space equals space plus-or-minus 2

From (1), we obtain

minus 4 space equals space fraction numerator a open square brackets 1 minus open parentheses 2 close parentheses squared close square brackets over denominator 1 minus 2 end fraction space f o r space r space equals 2
rightwards double arrow minus 4 space equals space fraction numerator a open parentheses 1 minus 4 close parentheses over denominator minus 1 end fraction
rightwards double arrow minus 4 space equals space a open parentheses 3 close parentheses
rightwards double arrow a space equals space fraction numerator minus 4 over denominator 3 end fraction
A l s o comma space
minus 4 space equals space fraction numerator a open square brackets 1 minus open parentheses minus 2 close parentheses squared close square brackets over denominator 1 minus open parentheses minus 2 close parentheses end fraction space f o r space r space equals minus 2
rightwards double arrow minus 4 space equals space fraction numerator a open parentheses 1 minus 4 close parentheses over denominator 1 plus 2 end fraction
rightwards double arrow minus 4 space equals space fraction numerator a open parentheses minus 3 close parentheses over denominator 3 end fraction
rightwards double arrow a space equals space 4
T h u s comma space t h e space r e q u i r e d space G. P. space i s
fraction numerator minus 4 over denominator 3 end fraction comma space fraction numerator minus 8 over denominator 3 end fraction comma space fraction numerator minus 16 over denominator 3 end fraction space comma space... space o r space 4 comma space minus 8 comma space 16 comma space minus 32 comma space........

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