Class 12 Mathematics - Chapter Inverse Trigonometric Functions NCERT Solutions | Find the value of if \begin{align} sin^{
Welcome to the NCERT Solutions for Class 12th Mathematics - Chapter Inverse Trigonometric Functions. This page offers a step-by-step solution to the specific question from Excercise 1 , Question 13: find the value of if begin align sin 1 x y....
Question 13
Find the value of if \begin{align} sin^{-1} x= y,\end{align}
Find the value of if \begin{align} sin^{-1} x= y,\end{align}
then
\begin{align} (A) 0 ≤ y ≤ x \;\;\;\;\; (B) -\frac{\pi}{2} ≤ y ≤ \frac{\pi}{2} \end{align}
\begin{align} (C)\; 0 < y < \pi \;\;\;\;\; (D) -\frac{\pi}{2} < y < \frac{\pi}{2} \end{align}
Answer
It is given that sin−1 x = y.
We know that the range of the principal value branch of sin−1 is
\begin{align} \left[-\frac{\pi}{2} ,\frac{\pi}{2}\right] \end{align}
Therefore,
\begin{align} (B) -\frac{\pi}{2} ≤ y ≤ \frac{\pi}{2} \end{align}
More Questions From Class 12 Mathematics - Chapter Inverse Trigonometric Functions
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