Class 12 Mathematics - Chapter Inverse Trigonometric Functions NCERT Solutions | Find the principal value of \begin{align

Welcome to the NCERT Solutions for Class 12th Mathematics - Chapter Inverse Trigonometric Functions. This page offers a step-by-step solution to the specific question from Excercise ".$ex_no." , Question 3: find the principal value of begin align cosec....
Question 3

Find the principal value of \begin{align} cosec^{-1}\left({2}\right)\end{align}

Answer

\begin{align} Let \;\; cosec^{-1}\left({2}\right)=y \;\;Then\;\; cosec y = 2 = cosec\left(\frac{\pi}{6}\right)\end{align} 

We know that the range of the principal value branch of cosec−1 is
\begin{align} \left[-\frac{\pi}{2},\frac{\pi}{2}\right] - \left(0 \right). \end{align}
Therefore, the principal value of
\begin{align} \frac{\pi}{6}\end{align}
 
 
 

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