Class 12 Mathematics - Chapter Integrals NCERT Solutions | sin 2x – 4e3x
sin 2x – 4e3x
The anti derivative of sin 2x – 4e3x is the function of x whose derivative is sin 2x – 4e3x.
It is known that,
\begin{align} \frac {d}{dx} \left(-\frac{1}{2}cos 2x – \frac {4}{3} e^{3x}\right) = sin2x – 4e^{3x} \end{align}
Therefore, the anti derivative of (sin 2x – 4e3x) is \begin{align} \left(-\frac{1}{2}cos 2x – \frac {4}{3} e^{3x}\right) \end{align}
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