Class 12 Mathematics - Chapter Integrals NCERT Solutions | \begin{align} \int \frac{x^3 + 5x^2 - 4}
\begin{align} \int \frac{x^3 + 5x^2 - 4}{x^2} . dx\end{align}
\begin{align} \int \frac{x^3 + 5x^2 - 4}{x^2} . dx\end{align}
\begin{align} =\int \left(x + 5 - 4x^{-2}\right) . dx\end{align}
\begin{align} =\int x .dx + 5 \int 1.dx- 4 \int x^{-2} .dx\end{align}
\begin{align} =\frac {x^2}{2} + 5x + 4 \left(\frac{x^{-1}}{-1}\right) + C\end{align}
\begin{align} =\frac {x^2}{2} + 5x + \frac{4}{x} + C\end{align}
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(iii) Relation R in the set A = {1, 2, 3, 4, 5, 6} as
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(iv) Relation R in the set Z of all integers defined as
R = {(x, y): x − y is as integer}
(v) Relation R in the set A of human beings in a town at a particular time given by
(a) R = {(x, y): x and y work at the same place}
(b) R = {(x, y): x and y live in the same locality}
(c) R = {(x, y): x is exactly 7 cm taller than y}
(d) R = {(x, y): x is wife of y}
(e) R = {(x, y): x is father of y} - Q:- Find the rate of change of the area of a circle with respect to its radius r when
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Given that E and F are events such that P(E) = 0.6, P(F) = 0.3 and P(E ∩ F) = 0.2, find P (E|F) and P(F|E).
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