Class 12 Mathematics - Chapter Differential Equations NCERT Solutions | y = ex +1 : yn -y' = 0
y = ex +1 : yn -y' = 0
y = ex +1
Differentiating both sides of this equation with respect to x, we get:
\begin{align}\frac{dy}{dx}=\frac{d}{dx}(e^x + 1)\end{align}
=> y' = ex ...(1)
Now, differentiating equation (1) with respect to x, we get:
\begin{align}\frac{d}{dx}(y^{'})=\frac{d}{dx}(e^x)\end{align}
=> y'' = ex
Substituting the values of y' and y'' in the given differential equation, we get the L.H.S. as:
y'' - y' = ex - ex = 0 = R.H.S.
Thus, the given function is the solution of the corresponding differential equation.
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