The order of the differential equation
\begin{align}2x^2\frac{d^2y}{dx^2}\;- \;3\frac{dy}{dx}\;+ y=\;0\end{align}
is (A) 2 (B) 1 (C) 0 (D) not defined
\begin{align}2x^2\frac{d^2y}{dx^2}\;- \;3\frac{dy}{dx}\;+ y=\;0\end{align}
The highest order derivative present in the given differential equation is
\begin{align}\frac{d^2y}{dx^2}\end{align}
Therefore, its order is two.
Hence, the correct answer is A.
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