Class 11 Chemistry - Chapter Thermodynamics NCERT Solutions | Calculate the entropy change in surround

Welcome to the NCERT Solutions for Class 11th Chemistry - Chapter Thermodynamics. This page offers a step-by-step solution to the specific question from Excercise ".$ex_no." , Question 22: calculate the entropy change in surroundings when....
Question 22

Calculate the entropy change in surroundings when 1.00 mol of H2O(l) is formed under standard conditions. ΔfH0 = –286 kJ mol–1.

Answer

It is given that 286 kJ mol-1of heat is evolved on the formation of 1 mol of H2O(l). Thus, an equal amount of heat will be absorbed by the surroundings.

qsurr = +286 kJ mol-1

Entropy change (ΔSsurr) for the surroundings =  qsurr / 7

= 286 kJ mol-1  / 298k

\therefore  ΔSsurr = 959.73 J mol-1K-1

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