Class 11 Chemistry - Chapter Thermodynamics NCERT Solutions | Comment on the thermodynamic stability o

Welcome to the NCERT Solutions for Class 11th Chemistry - Chapter Thermodynamics. This page offers a step-by-step solution to the specific question from Exercise 1, Question 21: comment on the thermodynamic stability of no g g....
Question 21

Comment on the thermodynamic stability of NO(g), given

1/2 N2(g) + 1/2 O2(g) → NO(g) ; ΔrH0 = 90 kJ mol–1

NO(g) + 1/2 O2(g) → NO2(g) : ΔrH0= –74 kJ mol–1

Answer

The positive value of ΔrH indicates that heat is absorbed during the formation of NO(g). This means that NO(g) has higher energy than the reactants (N2 and O2). Hence, NO(g) is unstable. The negative value of ΔrH indicates that heat is evolved during the formation of NO2(g) from NO(g) and O2(g). The product, NO2(g) is stabilized with minimum energy. Hence, unstable NO(g) changes to stable NO2(g).

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