Class 11 Chemistry - Chapter Thermodynamics NCERT Solutions | Enthalpy of combustion of carbon to CO2&

Welcome to the NCERT Solutions for Class 11th Chemistry - Chapter Thermodynamics. This page offers a step-by-step solution to the specific question from Exercise 1, Question 11: enthalpy of combustion of carbon to co2 nbsp is 3....
Question 11

Enthalpy of combustion of carbon to COis -393.5 kJ mol-1. Calculate the heat released upon formation of 35.2 g of COfrom carbon and dioxygen gas.

Answer

Formation of CO2 from carbon and dioxygen gas can be represented as:

C(s) + O2(g)  → CO2(g)           ΔfH = -393.5 kJ mol-1

(1 mole = 44 g)

Heat released on formation of 44g CO= -393.5 kJ mol-1

\therefore Heat released on formation of 35.2 g CO2

= [ -393.5kJ mol-1  /  44g  ]  x  35.2g

= -314.8 kJ mol-1

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