Class 12 Chemistry - Chapter The Solid State NCERT Solutions | Analysis shows that nickel oxide has the

Welcome to the NCERT Solutions for Class 12th Chemistry - Chapter The Solid State. This page offers a step-by-step solution to the specific question from Exercise 2, Question 16: analysis shows that nickel oxide has the formula n....
Question 16

Analysis shows that nickel oxide has the formula Ni0.98 O1.00. What fractions of nickel exist as Ni2+and Ni3+ions?

Answer

The formula of nickel oxide is Ni0.98 O1.00.

Therefore, the ratio of the number of Ni atoms to the number of O atoms,

Ni : O = 0.98 : 1.00 = 98 : 100

Now, total charge on 100 O2 - ions = 100 × ( - 2) = - 200

Let the number of Ni2+ions be x.

So, the number of Ni3+ions is 98 - x.

Now, total charge on Ni2+ions = x(+2) = +2x

And, total charge on Ni3+ions = (98 - x)(+3) = 294 - 3x

Since, the compound is neutral, we can write: 2x+ (294 - 3x) + ( - 200) = 0

⇒ - x+ 94 = 0 ⇒ x= 94

Therefore, number of Ni2+ions = 94

And, number of Ni3+ions = 98 - 94 = 4

Hence, fraction of nickel that exists as Ni2+ = 94/98 = 0.959

And, fraction of nickel that exists as Ni3+ = 4/98 = 0.041

Alternatively, fraction of nickel that exists as Ni3+= 1 - 0.959 = 0.041

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