The work function for caesium atom is 1.9 eV. Calculate
(a) the threshold wavelength and
(b) the threshold frequency of the radiation. If the caesium element is irradiated with a wavelength 500 nm, calculate the kinetic energy and the velocity of the ejected photoelectron.
A) Work function of caesium (WO) = hvo
Therefore vo = WO/h = 1.9 x1.602 x10-19 / 6.626x10-34
= 4.59x1014/sec
B) λo =c/vo = 3x108 / 4.59x1014 = 6.54x10-7m
C) K.E of ejected electron = h(v-vo) = hc(1/λ – 1/ λo)
=(6.626x3x10-26) (1/500x10-9 – 1/654x10-9)
=(6.626x3x10-26) / 10-9(154/500x654)
= 9.36x10-20J
k.E = 1mv2/2 = 9.36x10-20J
=9.1x10-31/2 = 9.36x10-20J
Or
v2 = 20.55x1010m2s-2
Or
v = 4.53x105ms-1
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A photon of wavelength 4 × 10–7 m strikes on metal surface, the work function of the metal being 2.13 eV. Calculate
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(iv) CH2=CHCN,
(v) C6H6
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(iii) CH4
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(b) NaHSO4
(c) H4P2O7
(d) K2MnO4
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(f) NaBH4
(g) H2S2O7
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(ii) whose value is independent of path
(iii) used to determine pressure volume work
(iv) whose value depends on temperature only.
A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased.
a) What is the initial effect of the change on vapour pressure?
b) How do rates of evaporation and condensation change initially?
c) What happens when equilibrium is restored finally and what will be the final vapour pressure?
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Isotope |
Isotopic molar mass |
Abundance |
36Ar |
35.96755 gmol–1 |
0.337% |
38Ar |
37.96272 gmol–1 |
0.063% |
40Ar |
39.9624 gmol–1 |
99.600% |
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Part 1st ka ans second wala h and vice versa
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