Class 11 Chemistry - Chapter Structure of Atom NCERT Solutions | Calculate the wave number for the longes

Welcome to the NCERT Solutions for Class 11th Chemistry - Chapter Structure of Atom. This page offers a step-by-step solution to the specific question from Excercise ".$ex_no." , Question 17: calculate the wave number for the longest waveleng....
Question 17

Calculate the wave number for the longest wavelength transition in the Balmer series of atomic hydrogen.

Answer

According to Balmer formula

ṽ=1/λ = RH[1/n12-1/n22]

For the Balmer series, ni = 2.

Thus, the expression of wavenumber(ṽ) is given by,

Wave number (ṽ) is inversely proportional to wavelength of transition. Hence, for the longest wavelength transition, ṽ has to be the smallest.

For ṽ to be minimum, nf should be minimum. For the Balmer series, a transition from ni = 2 to nf = 3 is allowed. Hence, taking nf = 3,we get:

ṽ= 1.5236 × 106 m–1

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