What is the number of photons of light with a wavelength of 4000 pm that provide 1 J of energy?
Energy (E) of a photon = hc/λ
Where,λ = wavelength of light = 4000 pm = 4000 ×10–12 m = 4x 10-9 m
c = velocity of light in vacuum = 3 × 108 m/s
h = Planck’s constant = 6.626 × 10–34 Js
thefore the energy of photon (E)
= 6.626 × 10–34 Js X 3 × 108 m/s / 4x 10-9 m = 4.965 x 10-16 J
Now 4.965 x 10-16 J is the energy of = 1 photon
Therefore 1 J will be the energy of = 1/4.965 x 10-16 J = 2.014 x 1015 photons
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(a) n = 1, l = 0;
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(d) n = 4; l =3.
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(b) NaHSO4
(c) H4P2O7
(d) K2MnO4
(e) CaO2
(f) NaBH4
(g) H2S2O7
(h) KAl(SO4)2.12 H2O
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(i) used to determine heat changes
(ii) whose value is independent of path
(iii) used to determine pressure volume work
(iv) whose value depends on temperature only.
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a) What is the initial effect of the change on vapour pressure?
b) How do rates of evaporation and condensation change initially?
c) What happens when equilibrium is restored finally and what will be the final vapour pressure?
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(a) Li (b) Na (c) K (d) Cs
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CH4 (g) + H2O (g) ↔ CO (g) + 3H2 (g)
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(i) increasing the pressure
(ii) increasing the temperature
(iii) using a catalyst ?
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(b) Write suitable chemical equations to show their nature.
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(i) empirical formula,
(ii) molar mass of the gas, and
(iii) molecular formula.
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Write down the reactions involved during the formation of photochemical smog.
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How can you explain higher stability of BCl3 as compared to TlCl3?
The right answer is 2.012Ã10^16
Yaah this is not the correct answer
This is not correct answer
Correct answer will be 2.012ÃÃ10^16 photons
Sir, the answer will be 2.014*10^16
this is shit
I have not understood nicely.....
Thank u.... for this solution...
Energy of photon will be 4.965 * 10^-17 and hence the answer will be 2.014 * 10^16 photons
Write but some corrections needed