What is the number of photons of light with a wavelength of 4000 pm that provide 1 J of energy?
Energy (E) of a photon = hc/λ
Where,λ = wavelength of light = 4000 pm = 4000 ×10–12 m = 4x 10-9 m
c = velocity of light in vacuum = 3 × 108 m/s
h = Planck’s constant = 6.626 × 10–34 Js
thefore the energy of photon (E)
= 6.626 × 10–34 Js X 3 × 108 m/s / 4x 10-9 m = 4.965 x 10-16 J
Now 4.965 x 10-16 J is the energy of = 1 photon
Therefore 1 J will be the energy of = 1/4.965 x 10-16 J = 2.014 x 1015 photons
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(b) NaHSO4
(c) H4P2O7
(d) K2MnO4
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(iii) used to determine pressure volume work
(iv) whose value depends on temperature only.
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If initially pure BrCl is present at a concentration of 3.3 × 10–3 mol L–1, what is its molar concentration in the mixture at equilibrium?
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Complete the following chemical reactions.
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(ii) MnO-4(aq) + H2O2(aq) →
(iii) CaO(s) + H2O(g) →
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At 700 K, equilibrium constant for the reaction:
H2 (g) + I2 (g) ↔ 2HI (g)
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The right answer is 2.012Ã10^16
Yaah this is not the correct answer
This is not correct answer
Correct answer will be 2.012ÃÃ10^16 photons
Sir, the answer will be 2.014*10^16
this is shit
I have not understood nicely.....
Thank u.... for this solution...
Energy of photon will be 4.965 * 10^-17 and hence the answer will be 2.014 * 10^16 photons
Write but some corrections needed