Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar.
(R = 0.083 bar dm3 K–1 mol–1).
Given,
Amount of the gas, n = 4.0 mol
Volume of the gas, V = 5 dm3
Pressure of the gas, p = 3.32 bar
R = 0.083 bar dm3 K–1 mol–1
From the ideal gas equation, we get
pV = nRT
⇒ T = pV / nR
= (3.32x5) / (4x0.083)
= 50K
Hence, the required temperature is 50 K.
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pressure of gas filled in a closed cylinder 273k is 4 atm . calulate the temp of the gas when its pressure is 5 atm pleas send me the ans as soon as posible