The drain cleaner, Drainex contains small bits of aluminum which react with caustic soda to produce dihydrogen. What volume of dihydrogen at 20 °C and one bar will be released when 0.15g of aluminum reacts?
Aluminium reacts with caustic soda in accordance with the reaction
The reaction of aluminium with caustic soda can be represented as:
Therefore volume of hydrogen at STP released when 0.15g of Al reactsv
=0.15 x 3 x 22.4 /54 = 187ml
Now P1 = 1 bar,
P2 = 1 bar
T1 = 273 K
T2 = 20 + 273 = 293 K
V1 = 187 ml
V2 = x
When pressure is held constant,then
V2 = P1 V1 T2 / P2 T1
OR
x = 1 X 187 X 293 / 0.987 X 273
= 201 ml
Therefore, 201 mL of dihydrogen will be released.
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(ii) CH3CH=CH2,
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(iv) CH2=CHCN,
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(iii) CH4
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(a) NaH2PO4
(b) NaHSO4
(c) H4P2O7
(d) K2MnO4
(e) CaO2
(f) NaBH4
(g) H2S2O7
(h) KAl(SO4)2.12 H2O
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(iii) used to determine pressure volume work
(iv) whose value depends on temperature only.
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c) What happens when equilibrium is restored finally and what will be the final vapour pressure?
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I2(g) ↔ 2l (g)
Calculate Kp for the equilibrium.
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thank u
H2=22.4 how
Why you convert temprature in kelvin although all the quantities are in cgs
Why you take T1 273? And what is the base of it
Nice
How p1=1 and p2=1
22.4L converted to litre
What is 22400 here