Use the data given in the following tabl | Class 11 Chemistry Chapter Some Basic Concepts of Chemistry, Some Basic Concepts of Chemistry NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Some Basic Concepts of Chemistry. This page offers a step-by-step solution to the specific question from Exercise 1, Question 32: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 32:

Use the data given in the following table to calculate the molar mass of naturally occurring argon isotopes:

Isotope

Isotopic molar mass

Abundance

36Ar

35.96755 gmol–1

0.337%

38Ar

37.96272 gmol–1

0.063%

40Ar

39.9624 gmol–1

99.600%

Answer:

Molar mass of argon =

Atomic mass of 36Ar = 35.96755 & abundance = 0.337

Or

total atomic mass of 36Ar = 35.96755 * 0.337= 0.121g/mol

Atomic mass of 38Ar = 37.96272 & abundance = 0.063

Or

total atomic mass of 38Ar = 37.96272 * 0.063= 0.024g/mol

Atomic mass of 40Ar =39.9624 & abundance = 99.600

Or

total atomic mass of 40Ar = 39.9624 * 99.600= 39.802g/mol

 

Therefore molar mass of argon = total mass of 36Ar+ total mass of 38Ar + atomic mass of 40Ar

= 0.121 + 0.024 + 39.802= 39.947 g/mol


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Comments

  • Motilal Sanjenbam
  • Oct 07, 2020

Thank you so much


  • Sariga
  • Jun 30, 2019

Thank you


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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 32: Use the data given in the following table to calculate the molar mass of naturally occurring argon i....