Class 11 Chemistry - Chapter Some Basic Concepts of Chemistry NCERT Solutions | Use the data given in the following tabl

Welcome to the NCERT Solutions for Class 11th Chemistry - Chapter Some Basic Concepts of Chemistry. This page offers a step-by-step solution to the specific question from Exercise 1, Question 32: use the data given in the following table to calcu....
Question 32

Use the data given in the following table to calculate the molar mass of naturally occurring argon isotopes:

Isotope

Isotopic molar mass

Abundance

36Ar

35.96755 gmol–1

0.337%

38Ar

37.96272 gmol–1

0.063%

40Ar

39.9624 gmol–1

99.600%

Answer

Molar mass of argon =

Atomic mass of 36Ar = 35.96755 & abundance = 0.337

Or

total atomic mass of 36Ar = 35.96755 * 0.337= 0.121g/mol

Atomic mass of 38Ar = 37.96272 & abundance = 0.063

Or

total atomic mass of 38Ar = 37.96272 * 0.063= 0.024g/mol

Atomic mass of 40Ar =39.9624 & abundance = 99.600

Or

total atomic mass of 40Ar = 39.9624 * 99.600= 39.802g/mol

 

Therefore molar mass of argon = total mass of 36Ar+ total mass of 38Ar + atomic mass of 40Ar

= 0.121 + 0.024 + 39.802= 39.947 g/mol

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