Class 12 Chemistry - Chapter Solutions NCERT Solutions | Henry's law constant for the molalit

Welcome to the NCERT Solutions for Class 12th Chemistry - Chapter Solutions. This page offers a step-by-step solution to the specific question from Exercise 2, Question 35: henry 39 s law constant for the molality of metha....
Question 35

Henry's law constant for the molality of methane in benzene at 298 Kis 4.27 x 105 mm Hg. Calculate the solubility of methane in benzene at 298 Kunder 760 mm Hg.

Answer

As we know that

p = k x c

We have given p = 760 mm, k = 4.27 x 105

Putting the given values in equation

760 = 4.27 x 105 x c

Or

c = 760 / 4.27x 105

c = 178 x 10-5

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