Class 12 Chemistry - Chapter Solutions NCERT Solutions | An aqueous solution of 2% non-volatile s

Welcome to the NCERT Solutions for Class 12th Chemistry - Chapter Solutions. This page offers a step-by-step solution to the specific question from Excercise ".$ex_no." , Question 15: an aqueous solution of 2 non volatile solute exer....
Question 15

An aqueous solution of 2% non-volatile solute exerts a pressure of 1.004 bar at the normal boiling point of the solvent. What is the molar mass of the solute?

Answer

Here,

Vapour pressure of the solution at normal boiling point (p1) = 1.004 bar  (Given)

Vapour pressure of pure water at normal boiling point (p10) = 1.013 bar

Mass of solute, (w2) = 2 g

Mass of solvent (water), (w1) = 100 - 2 = 98 g

Molar mass of solvent (water), (M1) = 18 g mol - 1

According to Raoult's law,

(p10 - p1) / p10    (w2 x M1 ) / (Mw1 )

(1.013 - 1.004) / 1.013 =  (2 x 18) / (M2 x 98 )

0.009 / 1.013  =   (2 x 18) / (M2 x 98 )

M2  =  (2 x 18 x 1.013) / (0.009 x 98)

M2  = 41.35 g mol - 1

Hence, the molar mass of the solute is 41.35 g mol - 1.

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