Class 11 Chemistry - Chapter Redox Reactions NCERT Solutions | Justify giving reactions that among halo

Welcome to the NCERT Solutions for Class 11th Chemistry - Chapter Redox Reactions. This page offers a step-by-step solution to the specific question from Exercise 1, Question 15: justify giving reactions that among halogens fluo....
Question 15

Justify giving reactions that among halogens, fluorine is the best oxidant and among hydrohalic compounds, hydroiodic acid is the best reductant.

Answer

F2 can oxidize Cl- to Cl2, Br-  to Br2, and I- to I2 as:

F2(aq) + S2cl-(s)  →  2F-(aq)  +  Cl (g)

F2(aq) + 2Br-(aq)  →  2F-(aq)  + Br 2(l)

F2(aq) + 2l-(aq)  →  2F-(aq)  + 12(s)

 

On the other hand, Cl2, Br2, and I2 cannot oxidize F- to F2. The oxidizing power of halogens increases in the order of I2 < Br2 < Cl2 < F2. Hence, fluorine is the best oxidant.

HI and HBr can reduce H2SO4 to SO2, but HCl and HF cannot. Therefore, HI and HBr are stronger reductants than HCl and HF.

2HI + H2SO4  →  l2  +  SO2  +  2H2O

2HBr + H2SO4  →  Br2 + SO2  +  2H2O

Again, I- can reduce Cu2+ to Cu+, but Br- cannot.

4l-(aq)  +   2Cu2+(aq)  →  Cu2l2(s)  + l2(aq)

Hence, hydroiodic acid is the best reductant among hydrohalic compounds.

Thus, the reducing power of hydrohalic acids increases in the order of HF < HCl < HBr < HI.

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